The area of the region between the curves y = \sqrt{\frac{1+sinx}{cosx}} and y = \sqrt{\frac{1-sinx}{cosx}} bounded by the lines x = 0 and x = \pi/4 is

Correct Answer is : √2−1∫04t(1+t2)√1−t2 dt

\int^{\sqrt2-1}_{0}{t}/{(1+t^2)\sqrt{1-t^2} dt

\int^{\sqrt2-1}_{0}{4t}/{(1+t^2)\sqrt{1-t^2} dt

\int^{\sqrt2+1}_{0}{4t}/{(1+t^2)\sqrt{1-t^2} dt

\int^{\sqrt2+1}_{0}{t}/{(1+t^2)\sqrt{1-t^2} dt

JEE Mains Model Paper 19

Question : 54 of 90

Marks: +1, -0

The area of the region between the curves y = √

1+sinx

cosx

and y = √

1−sinx

cosx

bounded by the lines x = 0 and x =

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