If x^{\to}+y^{\to} = a^{\to} , x^{\to} \times y^{\to} = b^{\to} and x^{\to}.a^{\to} = 1 , then

Correct Answer is : →x = →a+→a×→ba2 , y = (a2−1)→a−(→a×→b)a2

x^{\to} = {a^{\to}+a^{\to}\timesb^{\to}}/a^2 , y = {(a^2-1)a^{\to}-(a^{\to}\timesb^{\to})}/a^2

x^{\to} = {a^{\to}-(a^{\to}\timesb^{\to})}/a^2 , y = {a^2+(a^{\to}\timesb^{\to})}/a^2

x^{\to} = {b^{\to}+(a^{\to}\timesb^{\to})}/a^2 , y can have any value

x^{\to} = {(b^2-1)b^{\to}-(a^{\to}\timesb^{\to})}/a^2 , y can have any value

JEE Mains Model Paper 15

Question : 69 of 90

Marks: +1, -0

→

and

→

= 1 , then

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