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Question : 78 of 90
Marks:
+1,
-0
Solution:
Let
be the unit vector
⇒
= α (
2++) + β (
−+)
⇒
|| = 1 ⇒
(2α+β)2 +
(α−β)2 +
(α+β)2 = 1
⇒ $$6α^2 + 4αβ +
3β2 = 1
is orthogonal to
5+2+6 so, 5 (2α + β) + 2 (α - β) + 6 (α + β) = 0
⇒ 18α + 3β = 0 ⇒ 2α = -β
∴
6α2−8α2 +
10α2 = 1
⇒
10α2 = 1
⇒ α = ±
⇒ β = ∓
∴
=
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