JEE Mains Model Paper 12

The height of the gasoline =

2

3

× 1.2 = 0.8 m
Since tank is closed, therefore volume of liquid inside it remain as such. Suppose free surfacemakes θ with the horizontal and x is the distance of free surface from A, thenVolume of AECBA = Volume of A'D'CB
∴

1

2

(2.4 + x) × 1.2 × 1.5 × 0.8
⇒ x = 0.8 m
From geometry tan θ =

CD

DE

= (

1.2

2.4−0.8

) = 0.75
And also tan θ =

ax

g

⇒ ax = g tan θ