JEE Mains Model Paper 12

In YDSE, path diference Δx = d sin q and For maxima Δx = nlwhere n = 0, ±1,±2, ±3.......
Given that d =

5λ

2

∴

5λ

2

sinθ = nλ ⇒ sinθ =

2π

5

-1 ≤ sinθ ≤ +1
⇒ -1 ≤

2n

5

≤ +1
⇒

−5

2

≤ n ≤

5

2

So, possible values of n are -2, -1, 0, 1, 2
Thus total number of 5 maximas will be formed