Solution of the equation (1 + x^2) \frac{dy}{dx} + y = e^{\tan^{-1}x} , y(0) = 0, is :

Correct Answer is : 2yetan−1x = e2tan−1x - 1

2ye^{\tan^{-1}x} = e^{2tan^{-1}x} - 1

2ye^{\tan^{-1}x} = e^{2tan^{-1}x}

ye^{\tan^{-1}x} = e^{2tan^{-1}x} + 1

JEE Mains Model Paper 12

Question : 27 of 90

Marks: +1, -0

Solution of the equation (1 + x2)

+ y = etan−1x , y(0) = 0, is :

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