\cos^{40}\theta + \sin^{58}\theta = 1 ⇒ θ =

Correct Answer is : {(2n+1)π2} ∪ {nπ} , n ∊ z

\{(2n+1)\pi/2\} ∪ \{n\pi\} , n ∊ z

\{(2n+1)\pi/2\} ∪ \{(3n+1)\pi/2\} , n ∊ z