JEE Mains Model Paper 10

20ml of 0.5M NaOH = 20 × 0.5 = 10 milli moles
= 10 milli equivalents
100ml of 0.1M HCl = 100 × 0.1 = 10 milli moles
= 10 milli equivalents
10 milli equivalents on neutralisation give heat = x kJ
1 g.eq = 1000 milli eq. will give = 100 x kJ
ΔH = - 100 x kJ