JEE Mains Model Paper 10

N2H4 – 10e– → Y (with two ‘N’ atoms)
Total O.N of two ‘N’ atoms in N2H4 is 2x + y = 0, 2x = - 4
Since it loses 10 moles of electrons, therefore, total O.N of two ‘N’ atoms increases by 10. i.e, thetotal O.N of two N-atoms is
Y = - 4 + 10 = + 6; O.N of each ‘N’ atom in Y = + 3