The trajectory of projectile, projected from the ground is given by {\y}= {\x}-\frac{ {\x}^2}{20}. Where {\x} and {\y} are measured in meter. The maximum height attained by the projectile will be. [8-Apr-2023 shift 2]

JEE Mains 8-Apr-2023 Shift 2 Solved Paper

Section: Physics

Question : 44 of 90

Marks: +1, -0

The trajectory of projectile, projected from the ground is given by y=x−‌

. Where x and y are measured in meter. The maximum height attained by the projectile will be.

[8-Apr-2023 shift 2]

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