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JEE Mains 8-Apr-2023 Shift 2 Solved Paper

Section: Physics
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Question : 37 of 90
 
Marks: +1, -0
Electric potential at a point ' P ' due to a point charge of 5×10−9C is 50V. The distance of ' P ' from the point charge is:
(Assume, ‌
1
4πε0
=9×10+9Nm2C−2 )
[8-Apr-2023 shift 2]
Validate
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