If {\A}=\left[\begin{array}{cc}1 & 5 \ \lambda & 10]\end{array}, {\A}^{-1}=\alpha A+\beta I and \alpha+\beta=-2, then 4 \alpha^2+\beta^2+\lambda^2 is equal to : [8-Apr-2023 shift 2]

JEE Mains 8-Apr-2023 Shift 2 Solved Paper

Section: Mathematics

Question : 3 of 90

Marks: +1, -0

If A=[

1	5
λ	10

],A−1=αA+βI and α+β=−2, then 4α2+β2+λ2 is equal to :

[8-Apr-2023 shift 2]

Go to Question:

Prev Question

Next Question

1−x	5
λ	10−x