Let the area enclosed by the lines x+y=2, y=0 x=0 and the curve f(x)=\min \{x^2+\frac{3}{4}, 1+[x]\} where [x] denotes the greatest integer \leq {\x}, be {\A}. Then the value of 12 {\A} is _______. [8-Apr-2023 shift 2]

JEE Mains 8-Apr-2023 Shift 2 Solved Paper

Section: Mathematics

Question : 25 of 90

Marks: +1, -0

Let the area enclosed by the lines x+y=2,y=0x=0 and the curve f(x)=min{x2+‌

,1+[x]} where [x] denotes the greatest integer ≤x, be A. Then the value of 12A is _______.

[8-Apr-2023 shift 2]

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