At any instant the velocity of a particle of mass 500 {\g} is (2 t \stackrel{\^}{i}+3 {\t}^2 \stackrel{\^}{ {\j}}) {\ms}^{-1}. If the force acting on the particle at {\t}=1 { s} is (\stackrel{\^}{ {\i}}+x \stackrel{\^}{ {\j}}) {\N}. Then the value of {\x} will be: [8-Apr-2023 shift 1]

JEE Mains 8-Apr-2023 Shift 1 Solved Paper

Section: Physics

Question : 43 of 90

Marks: +1, -0

At any instant the velocity of a particle of mass 500g is (2t

+3t2

)ms−1. If the force acting on the particle at t=1 s is (

)N. Then the value of x will be:

[8-Apr-2023 shift 1]

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