JEE Mains 8-Apr-2023 Shift 1 Solved Paper

Section: Mathematics
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Question : 2 of 90
 
Marks: +1, -0
Let P=[
‌
√3
2
‌
1
2
−‌
1
2
‌
√3
2
]
,A=[
11
01
]
and Q=PAPT. If PTQ2007P=[
ab
cd
]
, then 2a+b−3c−4d equal to
[8-Apr-2023 shift 1]
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