If the eqation of the plane containing the line x+2 y+3 z-4=02 x+y-z+5 and perpendicular to the plane { {\r}}^{\to}=(\stackrel{\^}{ {\i}}-\stackrel{\^}{ {\j}})+\lambda(\stackrel{\^}{i}+\stackrel{\^}{ {\j}}+\stackrel{\^}{ {\k}})+\mu(\stackrel{\^}{ {\i}}-2 \stackrel{\^}{ {\j}}+3 \stackrel{\^}{ {\k}}) is ax+by + {\cz}=4, then (a-b+c) is equal to [8-Apr-2023 shift 1]

JEE Mains 8-Apr-2023 Shift 1 Solved Paper

Section: Mathematics

Question : 18 of 90

Marks: +1, -0

If the eqation of the plane containing the line x+2y+3z−4=02x+y−z+5 and perpendicular to the plane

→

−

)+λ(

)+µ(

−2

) is ax+by +cz=4, then (a−b+c) is equal to

[8-Apr-2023 shift 1]

Go to Question:

Prev Question

Next Question