A capacitor of capacitance 150.0 \mu {\F} is connected to an alternating source of emf given by {\E}=36 \sin (120 \pi {\t}) {\V}. The maximum value of current in the circuit is approximatively equal to : [6-Apr-2023 shift 2]

JEE Mains 6-Apr-2023 Shift 2 Solved Paper

Section: Physics

Question : 41 of 90

Marks: +1, -0

A capacitor of capacitance 150.0µF is connected to an alternating source of emf given by E=36sin‌(120πt)V. The maximum value of current in the circuit is approximatively equal to :

[6-Apr-2023 shift 2]

√2A
2√2A
‌
1
√2
A
2A

Validate

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