JEE Mains 6-Apr-2023 Shift 2 Solved Paper

Section: Mathematics

Question : 1 of 90

Marks: +1, -0

If gcd(m,n)=1 and
12−22+32−42+......+(2021)2−(2022)2+(2023)2=1012m2n
then m2−n2 is equal to :

[6-Apr-2023 shift 2]

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