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JEE Mains 6-Apr-2023 Shift 1 Solved Paper

Section: Mathematics
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Question : 6 of 90
 
Marks: +1, -0
Let A=[aij]2×2, where aij≠0 for all i,j and A2=I. Let a be the sum of ∣ all diagonal elements of A and b=|A|. Then 3a2+4b2 is equal to :
[6-Apr-2023 shift 1]
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