JEE Mains 31-Jan-2023 Shift 1 Solved Paper

Section: Chemistry

Question : 35 of 90

Marks: +1, -0

When Cu2+ ion is treated with KI, a white precipitate, X appears in solution. The solution is titrated with sodium thiosulphate, the compound Y is formed. X and Y respectively are

[31-Jan-2023 Shift 1]

X=Cu2I2
Y=Na2S4O5
X=Cu2I2 Y=Na2S4O6
X=CuI2 Y=Na2S4O3
X=CuI2‌‌Y=Na2S4O6

Validate

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