Consider the following reaction Propanal + Methanal = \stackrel{\text{ (i)dil. }{──\xrightarrow {\NaOH}}_{(\ii)∆}_{(\iii)\NaCN}_{(\iv)\H_3\O^+} {\Product \B}_{(\C_5\H_8\O_3)} The correct statement for product {\B} is. It is [31-Jan-2023 Shift 1]

Correct Answer is : racemic mixture and gives a gas with saturated NaHCO3 solution

optically active and adds one mole of bromine

racemic mixture and gives a gas with saturated {\NaHCO}_3 solution

optically active alcohol and is neutrall

JEE Mains 31-Jan-2023 Shift 1 Solved Paper

Section: Chemistry

Question : 33 of 90

Marks: +1, -0

Consider the following reaction
Propanal + Methanal =

‌ (i)dil. ‌NaOH

─────────▶

(ii)∆

(iii)‌NaCN

(iv)H3O+

Product‌B

(C5H8O3)

The correct statement for product B is. It is

[31-Jan-2023 Shift 1]

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