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JEE Mains 31-Jan-2023 Shift 1 Solved Paper

Section: Physics
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Question : 27 of 90
 
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Expression for an electric field is given by
→
E
=4000x2‌
^
i
‌
V
m
. The electric flux through the cube of side 20‌cm when placed in electric field (as shown in the figure) is ________ V‌cm.
[31-Jan-2023 Shift 1]
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