An electron accelerated through a potential difference V_1 has a de-Broglie wavelength of \lambda. When the potential is changed to {\V}_2, its de-Broglie wavelength increases by 50 \%. The value of ( { {\V}_1}/{ {\V}_2}) is equal to : [30-Jan-2023 Shift 2]

JEE Mains 30-Jan-2023 Shift 2 Solved Paper

Section: Physics

Question : 15 of 90

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An electron accelerated through a potential difference V1 has a de-Broglie wavelength of λ. When the potential is changed to V2, its de-Broglie wavelength increases by 50%. The value of (‌

) is equal to :

[30-Jan-2023 Shift 2]

3
‌
9
4
‌
3
2
4

Validate

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