A small object at rest, absorbs a light pulse of power 20 {\mW} and duration 300 {\ns}. Assuming speed of light as 3 \times 10^8 {\m} \/ { s}. the momentum of the object becomes equal to : [30-Jan-2023 Shift 1]

Correct Answer is : 2×10−17kgm∕ s

0.5 \times 10^{-17} {\kg} {\m} \/ { s}

2 \times 10^{-17} {\kg} {\m} \/ { s}

3 \times 10^{-17} {\kg} {\m} \/ { s}

1 \times 10^{-17} {\kg} {\m} \/ { s}

JEE Mains 30-Jan-2023 Shift 1 Solved Paper

Section: Physics

Question : 7 of 90

Marks: +1, -0

A small object at rest, absorbs a light pulse of power 20‌mW and duration 300‌ns. Assuming speed of light as 3×108m∕ s. the momentum of the object becomes equal to :

[30-Jan-2023 Shift 1]

0.5×10−17‌kg‌m∕ s
2×10−17‌kg‌m∕ s
3×10−17‌kg‌m∕ s
1×10−17‌kg‌m∕ s

Validate

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