JEE Mains 30-Jan-2023 Shift 1 Solved Paper

Section: Mathematics
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Question : 64 of 90
 
Marks: +1, -0
Let the system of linear equations
‌x+y+kz=2
‌2x+3y−z=1
‌3x+4y+2z=k
have infinitely many solutions. Then the system
‌(k+1)x+(2k−1)y=7
‌(2k+1)x+(k+5)y=10‌ has: ‌
[30-Jan-2023 Shift 1]
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