JEE Mains 30-Jan-2023 Shift 1 Solved Paper

Section: Chemistry
© examsiri.com
Question : 59 of 90
 
Marks: +1, -0
A trisubstituted compound ' A ', C10H12O2 gives neutral FeCl3 test positive. Treatment of compound ' A ' with NaOH and CH3‌Br gives C11H14O2, with hydroiodic acid gives methyl iodide and with hot conc. NaOH gives a compound B,C10H12O2. Compound 'A' also decolorises alkaline KMnO4. The number of π bond/s present in the compound ' A ' is _______.
[30-Jan-2023 Shift 1]
  • Your Answer:
Go to Question: