JEE Mains 30-Jan-2023 Shift 1 Solved Paper
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As per the given figure, a small ball P slides down the quadrant of a circle and hits the other ball Q of equal mass which is initially at rest. Neglecting the effect of friction and assume the collision to be elastic, the velocity of ball Q after collision will be : ( g = 10 m ∕ s 2 )
[30-Jan-2023 Shift 1]
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