JEE Mains 29-July-2022 Shift 2 Solved Paper

Length of wire Y is very high compared to length of wire X. So we can assume length of wire Y is infinite compare to wire X.
Magnetic field due to wire y from 5‌cm from wire towards wire X is,
B=‌

µ0I1

2πd

=‌

µ0×3

2π×0.05

And direction of B is outward.
Now force on wire X due to wire Y,
FYX=I2Bl
=2×‌

µ0×3

2π×0.05

×0.5
=1.2×10−5N
Current flowing in both the wire in same direction so both wire will attract each other with equal force.
∴FYX=FXY
∴FXY=1.2×10−5N, attractive force towards wire X.