JEE Mains 29-July-2022 Shift 2 Solved Paper

Charge on the left surface of plate A=‌

‌ Total charge ‌

2

=‌

q1+q2

2

Let right surface of plate A has charge =x
And total charge on plate A=q1
∴q1= Charge on left surface of plate A+ Charge on right surface of plate A
=‌

q1+q2

2

+x
⇒x=q1−‌

q1+q2

2

=‌

2q1−q1−q2

2

=‌

q1−q2

2

Let potential difference between two plates =v
For capacitor we know,
q=CV
∴‌

q1−q2

2

=CV
⇒V=‌

q1−q2

2C