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JEE Mains 29-July-2022 Shift 2 Solved Paper

Section: Mathematics
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Question : 18 of 90
 
Marks: +1, -0
Let
→
a
,
→
b
,
→
c
 be three coplanar concurrent vectors such that angles between any two of them is same. If the product of their magnitudes is 14 and (
→
a
×
→
b
)â‹…(
→
b
×
→
c
)+(
→
b
×
→
c
)â‹…(
→
c
×
→
a
)+(
→
c
×
→
a
)â‹…(
→
a
×
→
b
)=168, then |
→
a
|+|
→
b
|+|
→
c
| is equal to:
[29-Jul-2022-Shift-2]
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