JEE Mains 29-July-2022 Shift 2 Solved Paper

Section: Mathematics

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Question : 10 of 90

Marks: +1, -0

Let y=y(x) be the solution curve of the differential equation ‌

dy

dx

+(‌

2x2+11x+13

x3+6x2+11x+6

)y=‌

(x+3)

x+1

,x>−1, which passes through the point (0,1). Then y(1) is equal to:

[29-Jul-2022-Shift-2]

‌
1
2
‌
3
2
‌
5
2
‌
7
2

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