JEE Mains 29-July-2022 Shift 1 Solved Paper

Resistance of a conductivity cell (cell constant 129m−1 ) filled with 74.5‌ppm solution of KCl is 100Ω (labelled as solution 1). When the same cell is filled with KCl solution of 149‌ppm, the resistance is 50Ω (labelled as solution 2). The ratio of molar conductivity of solution 1 and solution 2 is i.e. ‌

∧1

∧2

=x×10−3. The value of x is _______.(Nearest integer)
Given, molar mass of KCl is 74.5gmol−1.