One mole of a monoatomic gas is mixed with three moles of a diatomic gas. The molecular specific heat of mixture at constant volume is \frac{\alpha^2}{4} {\RJ} \/ {\molK}; then the value of \alpha will be _______ . (Assume that the given diatomic gas has no vibrational mode). [29-Jul-2022-Shift-1]

JEE Mains 29-July-2022 Shift 1 Solved Paper

Section: Physics

Question : 54 of 90

Marks: +1, -0

One mole of a monoatomic gas is mixed with three moles of a diatomic gas. The molecular specific heat of mixture at constant volume is ‌

α2

‌RJ∕molK; then the value of α will be _______ . (Assume that the given diatomic gas has no vibrational mode).

[29-Jul-2022-Shift-1]

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