The kinetic energy of emitted electron is E when the light incident on the metal has wavelength \lambda. To double the kinetic energy, the incident light must have wavelength: [29-Jul-2022-Shift-1]

{ {\hc}}/{ {\E} \lambda- {\hc}}

{ {\hc} \lambda}/{ {\E} \lambda+ {\hc}}

{ {\h} \lambda}/{ {\E} \lambda+ {\hc}}

{ {\hc} \lambda}/{ {\E} \lambda- {\hc}}

JEE Mains 29-July-2022 Shift 1 Solved Paper

Section: Physics

Question : 46 of 90

Marks: +1, -0

The kinetic energy of emitted electron is E when the light incident on the metal has wavelength λ. To double the kinetic energy, the incident light must have wavelength:

[29-Jul-2022-Shift-1]

‌
hc
Eλ−hc
‌
hc‌λ
Eλ+hc
‌
hλ
Eλ+hc
‌
hc‌λ
Eλ−hc

Validate

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