The angle of elevation of the top of a tower from a point A due north of it is \alpha and from a point B at a distance of 9 units due west of A is \cos ^{-1}(\frac{3}\sqrt{13}). If the distance of the point B from the tower is 15 units, then \cot \alpha is equal to : [29-Jul-2022-Shift-1]

JEE Mains 29-July-2022 Shift 1 Solved Paper

Section: Mathematics

Question : 11 of 90

Marks: +1, -0

The angle of elevation of the top of a tower from a point A due north of it is α and from a point B at a distance of 9 units due west of A is cos−1(‌

√13

). If the distance of the point B from the tower is 15 units, then cot‌α is equal to :

[29-Jul-2022-Shift-1]

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