If the equation of the normal to the curve y=\frac{x-a}{(x+b)(x-2)} at the point (1,-3) is x-4 y=13 then the value of {\a}+ {\b} is equal to _______. [29-Jan-2023 Shift 2]

JEE Mains 29-Jan-2023 Shift 2 Solved Paper

Section: Mathematics

Question : 85 of 90

Marks: +1, -0

If the equation of the normal to the curve y=‌

x−a

(x+b)(x−2)

at the point (1,−3) is x−4y=13 then the value of a+b is equal to _______.

[29-Jan-2023 Shift 2]

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