JEE Mains 29-Jan-2023 Shift 1 Solved Paper
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Question : 80 of 90
Marks:
+1,
-0
Let y = f ( x ) be the solution of the differential equation y ( x + 1 ) dx − x 2 d y = 0 , y ( 1 ) = e . Then
f ( x ) is equal to
[29-Jan-2023 Shift 1]
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