JEE Mains 29-Jan-2023 Shift 1 Solved Paper

Section: Mathematics

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Question : 68 of 90

Marks: +1, -0

Let ‌‌f(x)=x+‌

a

π2−4

sin‌x+‌

b

π2−4

‌cos‌x, x∈ℝ be a function which satisfies f(x)=x+

π∕2

∫

0

sin‌(x+y)f(y)dy. Then (a+b) is equal to

[29-Jan-2023 Shift 1]

−π(π+2)
−2π(π+2)
−2π(π−2)
−π(π−2)

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