Solid Lead nitrate is dissolved in 1 litre of water. The solution was found to boil at 100.15^{\circ} {\C}. When 0.2 {\mol} of {\NaCl} is added to the resulting solution, it was observed that the solution froze at -0.8^{\circ} {\C}. The solutbility product of {\PbCl}_2 formed is ________ \times 10^{-6} at 298 {\K}. (Nearest integer) Given : {\K}_{ {\b}}=0.5 {\K} {\kg} {\mol}^{-1} and {\K}_{ {\f}}=1.8 {\kg} {\mol}^{-1}. Assume molality to be equal to molarity in all cases. [29-Jan-2023 Shift 1]

JEE Mains 29-Jan-2023 Shift 1 Solved Paper

Section: Chemistry

Question : 54 of 90

Marks: +1, -0

Solid Lead nitrate is dissolved in 1 litre of water. The solution was found to boil at 100.15∘C. When 0.2‌mol of NaCl is added to the resulting solution, it was observed that the solution froze at −0.8∘C. The solutbility product of PbCl2 formed is ________ ×10−6 at 298K. (Nearest integer)
Given : Kb=0.5K‌kg‌mol−1 and Kf=1.8‌kg‌mol−1.
Assume molality to be equal to molarity in all cases.

[29-Jan-2023 Shift 1]

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