JEE Mains 28-July-2022 Shift 2 Solved Paper
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Question : 55 of 90
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The potential energy of a particle of mass 4 kg in motion along the x -axis is given by U = 4 ( 1 − cos 4 x ) J . The time period of the particle for small oscillation ( s i n θ ≃ θ ) is (
) s . The value of K is ________.
[28-Jul-2022-Shift-2]
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