Let f(x)=a x^2+b x+c be such that f(1)=3, f(-2)=\lambda and f(3)=4. If f(0)+f(1)+f(-2)+f(3)=14, then \lambda is equal to : [28-Jul-2022-Shift-2]

JEE Mains 28-July-2022 Shift 2 Solved Paper

Section: Mathematics

Question : 4 of 90

Marks: +1, -0

Let f(x)=ax2+bx+c be such that f(1)=3,f(−2)=λ and f(3)=4. If f(0)+f(1)+f(−2)+f(3)=14, then λ is equal to :

[28-Jul-2022-Shift-2]

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