JEE Mains 28-July-2022 Shift 2 Solved Paper

A slab of dielectric constant K has the same cross-sectional area as the plates of a parallel plate capacitor and thickness ‌

3

4

d, where d is the separation of the plates. The capacitance of the capacitor when the slab is inserted between the plates will be :
(Given C0= capacitance of capacitor with air as medium between plates.)