Let {\z}=a+i b, b \neq 0 be complex numbers satisfying z^2=\overline{z} \cdot 2^{1-|z|}. Then the least value of n \in N, such that z^n=(z+1)^n, is equal to ________. [28-Jul-2022-Shift-2]

JEE Mains 28-July-2022 Shift 2 Solved Paper

Section: Mathematics

Question : 28 of 90

Marks: +1, -0

Let z=a+ib,b≠0 be complex numbers satisfying z2=z⋅21−|z|. Then the least value of n∈N, such that zn=(z+1)n, is equal to ________.

[28-Jul-2022-Shift-2]

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