Let \alpha, \beta be the roots of the equation x^2-\sqrt{2} x+\sqrt{6}=0 and \frac{1}{\alpha^2}+1, \frac{1}{\beta^2}+1 be the roots of the equation x^2+a x+b=0. Then the roots of the equation x^2-(a+b-2) x+(a+b+2)=0 are : [28-Jul-2022-Shift-2]

Correct Answer is : real and both negative

real and exactly one of them is positive

JEE Mains 28-July-2022 Shift 2 Solved Paper

Section: Mathematics

Question : 2 of 90

Marks: +1, -0

Let α,β be the roots of the equation x2−√2x+√6=0 and ‌

α2

+1,‌

β2

+1 be the roots of the equation x2+ax+b=0. Then the roots of the equation x2−(a+b−2)x+(a+b+2)=0 are :

[28-Jul-2022-Shift-2]

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