JEE Mains 28-July-2022 Shift 2 Solved Paper

Section: Mathematics

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Question : 11 of 90

Marks: +1, -0

Let y=y(x) be the solution curve of the differential equation ‌

dy

dx

+‌

1

x2−1

y=(‌

x−1

x+1

)1∕2,x>1 passing through the point (2,√‌

1

3

). Then √7y(8) is equal to:

[28-Jul-2022-Shift-2]

11+6loge3
19
12−2loge3
19−6loge3

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