Match List - I with List - II, match the gas evolved during each reaction. List - I List - II (A) ( {\NH}_4)_2 {\Cr}_2 {\O}_7 \stackrel{∆}{\rightarrow} (I) {\H}_2 (B) {\KMnO}_4+ {\HCl} \to (II) {\N}_2 (C) {\Al}+ {\NaOH}+ {\H}_2 {\O} \to (III) {\O}_2 (D) {\NaNO}_3 \stackrel{∆}{\rightarrow} (IV) {\Cl}_2 Choose the correct answer from the options given below: [28-Jul-2022-Shift-1]

Correct Answer is : (A)−(II),(B)−(IV),(C)−(I),(D)−(III)

( {\A})-( {\II}),( {\B})-( {\III}),( {\C})-( {\I}),( {\D})-( {\IV})

( {\A})-( {\III}),( {\B})-( {\I}),( {\C})-( {\IV}),( {\D})-( {\II})

( {\A})-( {\II}),( {\B})-( {\IV}),( {\C})-( {\I}),( {\D})-( {\III})

(A) -( III) ,( {\B})-( {\IV}),( {\C})-( {\I}),( {\D})-( {\II})

JEE Mains 28-July-2022 Shift 1 Solved Paper

Section: Chemistry

Question : 69 of 90

Marks: +1, -0

Match List - I with List - II, match the gas evolved during each reaction.

List - I

List - II

(A) (NH4)2Cr2O7

∆

⟶

(I) H2

(B) KMnO4+HCl→

(II) N2

(III) O2

(D) NaNO3

∆

⟶

(IV) Cl2

Choose the correct answer from the options given below:

[28-Jul-2022-Shift-1]

Go to Question:

Prev Question

Next Question