Choose the correct answer from the options given below: List - I Reaction (A) List - II Catalyst (A)4 {\NH}_3(g)+5 {\O}_2(g) \to 4 {\NO}(g)+6 {\H}_2 {\O}(g) (I) N O(g) (B) {\N}_2(g)+3 H_2(g) \to 2 N_3(g) (II) {\H}_2 {\SO}_4(l) (C) {\C}_{12} {\H}_{22} {\O}_{11}(a q)+ {\H}_2 {\O}(l) \to {{ {\C}} _6 {\H}_{12} {\O}_6}_{\Glucose}+ { {\C}}{_6 {\H}_{12} {\O}_6}_{\Fructose} (III) {\Pt}(s) (D) 2 {\SO}_2(g)+ {\O}_2(g) \to 2 {\SO}_3(g) (IV) F e(s) [28-Jul-2022-Shift-1]

Correct Answer is : (A)−( III) ,(B)−(IV),(C)−( II ),(D)−(I)

( {\A})-(II),( {\B})-( {\III}),( {\C})-( {\I}),( {\D})-( {\IV})

( {\A})-( {\III}),( {\B})-( {\II}),( {\C})-( {\I}),( {\D})-( {\IV})

( {\A})-( III) ,( {\B})-( {\IV}),( {\C})-( II ),( {\D})-( {\I})

(A) - (III), (B) - (II), (C) - (IV), (D) - (I)

JEE Mains 28-July-2022 Shift 1 Solved Paper

Section: Chemistry

Question : 64 of 90

Marks: +1, -0

Choose the correct answer from the options given below:

List - I Reaction (A)

List - II Catalyst

(A)4NH3(g)+5O2(g)→4‌NO(g)+6H2O(g)

(I) NO(g)

(B) N2(g)+3H2(g)→2N3(g)

(II) H2SO4(l)

C‌6H12O6

Glucose

+‌C

6H12O6

Fructose

(III) Pt(s)

(D) 2SO2(g)+O2(g)→2SO3(g)

(IV) Fe(s)

[28-Jul-2022-Shift-1]

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