The equation of current in a purely inductive circuit is 5 \sin (49 \pi t-30^{\circ}). If the inductance is 30 {\mH} then the equation for the voltage across the inductor, will be : \{. Let .\pi=\frac{22}{7}\} [28-Jul-2022-Shift-1]

Correct Answer is : 23.1sin(49πt+60∘)

1.47 \sin (49 \pi t-30^{\circ})

1.47 \sin (49 \pi t+60^{\circ})

23.1 \sin (49 \pi t-30^{\circ})

23.1 \sin (49 \pi t+60^{\circ})

JEE Mains 28-July-2022 Shift 1 Solved Paper

Section: Physics

Question : 44 of 90

Marks: +1, -0

The equation of current in a purely inductive circuit is 5‌sin(49πt−30∘). If the inductance is 30‌mH then the equation for the voltage across the inductor, will be :
{. Let .π=‌

}

[28-Jul-2022-Shift-1]

1.47‌sin(49πt−30∘)
1.47‌sin(49πt+60∘)
23.1‌sin(49πt−30∘)
23.1‌sin(49πt+60∘)

Validate

Go to Question:

Prev Question

Next Question