JEE Mains 28-July-2022 Shift 1 Solved Paper

Section: Mathematics
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Question : 20 of 90
 
Marks: +1, -0
The minimum value of the twice differentiable function f(x)=
∫
0
x
ex−tf′(t)‌dt
−(x2−x+1)ex
, x∈R‌, is ‌ :
[28-Jul-2022-Shift-1]
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