If the minimum value of f(x)=\frac{5 x^2}{2}+\frac{\alpha}{x^5}, x > 0, is 14 , then the value of \alpha is equal to: [28-Jul-2022-Shift-1]

JEE Mains 28-July-2022 Shift 1 Solved Paper

Section: Mathematics

Question : 17 of 90

Marks: +1, -0

If the minimum value of f(x)=‌

5x2

+‌

,x>0, is 14 , then the value of α is equal to:

[28-Jul-2022-Shift-1]

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